奋斗的八月,丰收的九月~

没想到今年考浙大的还挺多,最近很多来知乎提问我PAT准备方法的都是打算九月份拿下PAT的考研党,还有很多打赏留言要我有偿指导的,好像多数是跨考的,最近博客访问量直接是七月份的3倍多(日均访问量6000+,快要超过今年3月18日7569的最高记录了……你们继续努力……反正幸好我服务器撑得住2333333)……看来大家八月都在准备PAT呀(暑假都过去一大半了这才开始你们也是够拖延的哈哈哈),感谢对我博客代码的信任,那就提前祝考浙大的你们九月PAT考100啦~

PS:认为我大学利用课余时间更新1000+篇文章很辛苦记得打赏鼓励哦~万分感谢~我会一直努力维持代码的正确性和简洁性、PAT题解的完整性、博客服务器的稳定性~

  1. PAT系统迁移到PTA后,判题系统出现了一些变动,我已经将所有代码重新提交检验并更新代码,所有甲级和乙级题目的C/C++代码已经能够通过迁移后的PTA系统
  2. 由于很多人对C/C++语言不熟悉,我最近将逐步更新完善PAT甲级和乙级的Java版代码
  3. CCCC-GPLT(天梯赛)最新的一些题目最近将逐步更新完善;
  4. LeetCode题目近期将继Java、Python、Ruby、C++语言后更新Swift语言版本

[Java] 1030. Travel Plan (30)-PAT甲级

1030. Travel Plan (30)
A traveler’s map gives the distances between cities along the highways, together with the cost of each highway. Now you are supposed to write a program to help a traveler to decide the shortest path between his/her starting city and the destination. If such a shortest path is not unique, you are supposed to output the one with the minimum cost, which is guaranteed to be unique.

Input Specification:

Each input file contains one test case. Each case starts with a line containing 4 positive integers N, M, S, and D, where N (<=500) is the number of cities (and hence the cities are numbered from 0 to N-1); M is the number of highways; S and D are the starting and the destination cities, respectively. Then M lines follow, each provides the information of a highway, in the format:

City1 City2 Distance Cost

where the numbers are all integers no more than 500, and are separated by a space.

Output Specification:

For each test case, print in one line the cities along the shortest path from the starting point to the destination, followed by the total distance and the total cost of the path. The numbers must be separated by a space and there must be no extra space at the end of output.

Sample Input
4 5 0 3
0 1 1 20
1 3 2 30
0 3 4 10
0 2 2 20
2 3 1 20
Sample Output
0 2 3 3 40
题目大意:求起点到终点的最短路径最短距离和花费,要求首先路径最短,其次花费最少,要输出完整路径

PS:感谢github用户@fs19910227提供的pull request~

 

[Java] 1031. Hello World for U (20)-PAT甲级

1031. Hello World for U (20)
Given any string of N (>=5) characters, you are asked to form the characters into the shape of U. For example, “helloworld” can be printed as:
h    d
e     l
l     r
lowo
That is, the characters must be printed in the original order, starting top-down from the left vertical line with n1 characters, then left to right along the bottom line with n2 characters, and finally bottom-up along the vertical line with n3 characters. And more, we would like U to be as squared as possible — that is, it must be satisfied that n1 = n3 = max { k| k <= n2 for all 3 <= n2 <= N } with n1 + n2 + n3 – 2 = N.

Input Specification:
Each input file contains one test case. Each case contains one string with no less than 5 and no more than 80 characters in a line. The string contains no white space.

Output Specification:
For each test case, print the input string in the shape of U as specified in the description.

Sample Input:
helloworld!

Sample Output:
h      !
e      d
l       l
lowor

题目大意:用所给字符串按U型输出。n1和n3是左右两条竖线从上到下的字符个数,n2是底部横线从左到右的字符个数。
要求:
1. n1 == n3
2. n2 >= n1
3. n1为在满足上述条件的情况下的最大值

PS:感谢github用户@fs19910227提供的pull request~

[Java] 1027. Colors in Mars (20)-PAT甲级

1027. Colors in Mars (20)
People in Mars represent the colors in their computers in a similar way as the Earth people. That is, a color is represented by a 6-digit number, where the first 2 digits are for Red, the middle 2 digits for Green, and the last 2 digits for Blue. The only difference is that they use radix 13 (0-9 and A-C) instead of 16. Now given a color in three decimal numbers (each between 0 and 168), you are supposed to output their Mars RGB values.

Input

Each input file contains one test case which occupies a line containing the three decimal color values.

Output

For each test case you should output the Mars RGB value in the following format: first output “#, then followed by a 6-digit number where all the English characters must be upper-cased. If a single color is only 1-digit long, you must print a “0” to the left.

Sample Input
15 43 71
Sample Output
#123456

题目大意:给三个十进制的数,把它们转换为十三进制的数输出。要求在前面加上一个”#”号
分析:因为0~168的十进制转换为13进制不会超过两位数,所以这个两位数为(num / 13)(num % 13)构成的数字

PS:感谢github用户@fs19910227提供的pull request~

 

[Java] 1022. Digital Library (30)-PAT甲级

1022. Digital Library (30)
A Digital Library contains millions of books, stored according to their titles, authors, key words of their abstracts, publishers, and published years. Each book is assigned an unique 7-digit number as its ID. Given any query from a reader, you are supposed to output the resulting books, sorted in increasing order of their ID’s.

Input Specification:

Each input file contains one test case. For each case, the first line contains a positive integer N (<=10000) which is the total number of books. Then N blocks follow, each contains the information of a book in 6 lines:

Line #1: the 7-digit ID number;
Line #2: the book title — a string of no more than 80 characters;
Line #3: the author — a string of no more than 80 characters;
Line #4: the key words — each word is a string of no more than 10 characters without any white space, and the keywords are separated by exactly one space;
Line #5: the publisher — a string of no more than 80 characters;
Line #6: the published year — a 4-digit number which is in the range [1000, 3000].
It is assumed that each book belongs to one author only, and contains no more than 5 key words; there are no more than 1000 distinct key words in total; and there are no more than 1000 distinct publishers.

After the book information, there is a line containing a positive integer M (<=1000) which is the number of user’s search queries. Then M lines follow, each in one of the formats shown below:

1: a book title
2: name of an author
3: a key word
4: name of a publisher
5: a 4-digit number representing the year
Output Specification:

For each query, first print the original query in a line, then output the resulting book ID’s in increasing order, each occupying a line. If no book is found, print “Not Found” instead.

Sample Input:
3
1111111
The Testing Book
Yue Chen
test code debug sort keywords
ZUCS Print
2011
3333333
Another Testing Book
Yue Chen
test code sort keywords
ZUCS Print2
2012
2222222
The Testing Book
CYLL
keywords debug book
ZUCS Print2
2011
6
1: The Testing Book
2: Yue Chen
3: keywords
4: ZUCS Print
5: 2011
3: blablabla
Sample Output:
1: The Testing Book
1111111
2222222
2: Yue Chen
1111111
3333333
3: keywords
1111111
2222222
3333333
4: ZUCS Print
1111111
5: 2011
1111111
2222222
3: blablabla
Not Found

题目大意:模拟数字图书馆的查询功能。会给出n本书的信息,以及m个需要查询的命令,数字标号对应相应的命令,数字编号后面的字符串是查询的搜索词,要求输出这行命令以及输出满足条件的书的id,如果一个都没有找到,输出Not Found

PS:感谢github用户@fs19910227提供的pull request~