1005. Spell It Right (20)-PAT甲级真题

Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.

Input Specification:

Each input file contains one test case. Each case occupies one line which contains an N (<= 10100).

Output Specification:

For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.

Sample Input:

12345

Sample Output:

one five

题目大意：给一个非负正数N，计算N的每一位相加的和，然后输出和的每一位的英文读音～

分析：1、求出每一位相加的和sum 2、将sum转换为string s 3、将string s的每一位输出对应的英文读音～

#include <iostream>
using namespace std;
int main() {
    string a;
    cin >> a;
    int sum = 0;
    for (int i = 0; i < a.length(); i++)
        sum += (a[i] - '0');
    string s = to_string(sum);
    string arr[10] = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
    cout << arr[s[0] - '0'];
    for (int i = 1; i < s.length(); i++)
        cout << " " << arr[s[i] - '0'];
    return 0;
}

#include <iostream>

using namespace std;

int main() {

string a;

cin >> a;

int sum = 0;

for (int i = 0; i < a.length(); i++)

sum += (a[i] - '0');

string s = to_string(sum);

string arr[10] = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};

cout << arr[s[0] - '0'];

for (int i = 1; i < s.length(); i++)

cout << " " << arr[s[i] - '0'];

return 0;

}

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