LeetCode 328. Odd Even Linked List

Given a singly linked list, group all odd nodes together followed by the even nodes. Please note here we are talking about the node number and not the value in the nodes.

You should try to do it in place. The program should run in O(1) space complexity and O(nodes) time complexity.

Given 1->2->3->4->5->NULL,
return 1->3->5->2->4->NULL.

The relative order inside both the even and odd groups should remain as it was in the input.
The first node is considered odd, the second node even and so on …


分析:设立odd、even和evenHead三个指针,odd负责将所有奇数结点连接在一起,even负责把所有偶数结点连接在一起,而evenHead指向head->next表示偶数结点的头结点。将所有的串联好后将odd->next = evenHead, 最后返回head~


❤ 点击这里 -> 订阅《PAT | 蓝桥 | LeetCode学习路径 & 刷题经验》by 柳婼

❤ 点击这里 -> 订阅《从放弃C语言到使用C++刷算法的简明教程》by 柳婼

❤ 点击这里 -> 订阅PAT甲级乙级、蓝桥杯、GPLT天梯赛、LeetCode题解离线版