PAT 乙级 1017. A除以B (20) Java版

本题要求计算A/B，其中A是不超过1000位的正整数，B是1位正整数。你需要输出商数Q和余数R，使得A = B * Q + R成立。

输入格式：

输入在1行中依次给出A和B，中间以1空格分隔。

输出格式：

在1行中依次输出Q和R，中间以1空格分隔。

输入样例：

123456789050987654321 7

1	123456789050987654321 7

输出样例：

17636684150141093474 3

1	17636684150141093474 3

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Main {
  public static void main(String[] args) throws IOException {
    BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));
    String[] ab = bufferedReader.readLine().split(" ");
    bufferedReader.close();
    int b = Integer.parseInt(ab[1]), t = 0;
    StringBuilder stringBuffer = new StringBuilder();
    for (int i = 0; i < ab[0].length(); i++) {
      t = t * 10 + ab[0].charAt(i) - '0';
      stringBuffer.append((char)(t / b + '0'));
      t = t % b;
    }
    String result = stringBuffer.toString();
    if (result.charAt(0) == '0'  && result.length() != 1) {
      System.out.print(result.substring(1) + " " + t);
    } else {
      System.out.print(result + " " + t);
    }
  }
}

import java.io.BufferedReader;

import java.io.IOException;

import java.io.InputStreamReader;

public class Main {

public static void main(String[] args) throws IOException {

BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));

String[] ab = bufferedReader.readLine().split(" ");

bufferedReader.close();

int b = Integer.parseInt(ab[1]), t = 0;

StringBuilder stringBuffer = new StringBuilder();

for (int i = 0; i < ab[0].length(); i++) {

t = t * 10 + ab[0].charAt(i) - '0';

stringBuffer.append((char)(t / b + '0'));

t = t % b;

}

String result = stringBuffer.toString();

if (result.charAt(0) == '0' && result.length() != 1) {

System.out.print(result.substring(1) + " " + t);

} else {

System.out.print(result + " " + t);

}