[Java] 蓝桥杯BASIC-26 基础练习报时助手

问题描述
给定当前的时间，请用英文的读法将它读出来。
时间用时h和分m表示，在英文的读法中，读一个时间的方法是：
如果m为0，则将时读出来，然后加上“o’clock”，如3:00读作“three o’clock”。
如果m不为0，则将时读出来，然后将分读出来，如5:30读作“five thirty”。
时和分的读法使用的是英文数字的读法，其中0~20读作：
0:zero, 1: one, 2:two, 3:three, 4:four, 5:five, 6:six, 7:seven, 8:eight, 9:nine, 10:ten, 11:eleven, 12:twelve, 13:thirteen, 14:fourteen, 15:fifteen, 16:sixteen, 17:seventeen, 18:eighteen, 19:nineteen, 20:twenty。
30读作thirty，40读作forty，50读作fifty。
对于大于20小于60的数字，首先读整十的数，然后再加上个位数。如31首先读30再加1的读法，读作“thirty one”。
按上面的规则21:54读作“twenty one fifty four”，9:07读作“nine seven”，0:15读作“zero fifteen”。
输入格式
输入包含两个非负整数h和m，表示时间的时和分。非零的数字前没有前导0。h小于24，m小于60。
输出格式
输出时间时刻的英文。
样例输入
0 15
样例输出
zero fifteen

Java

package base26; import java.util.Scanner; public class Main { public static void main(String[] args) { String[] time = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen", "twenty", "thirty", "forty", "fifty"}; Scanner in = new Scanner(System.in); int n = in.nextInt(); int m = in.nextInt(); if (n / 20 >= 1) { time[0] = ""; System.out.print(time[20] + " " + time[n % 20] + " "); } else System.out.print(time[n] + " "); int i = m / 10; switch (i) { case 1: System.out.print(time[m]); break; case 2: System.out.print(time[20] + " " + time[m % 20]); break; case 3: System.out.print(time[21] + " " + time[m % 30]); break; case 4: System.out.print(time[22] + " " + time[m % 40]); break; case 5: System.out.print(time[23] + " " + time[m % 50]); break; default: if (m == 0) { System.out.print("o'clock"); } } } }

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42

package base26;

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        String[] time = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen", "twenty", "thirty", "forty", "fifty"};
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        int m = in.nextInt();

        if (n / 20 >= 1) {
            time[0] = "";
            System.out.print(time[20] + " " + time[n % 20] + " ");
        } else System.out.print(time[n] + " ");
        int i = m / 10;
        switch (i) {
            case 1:
                System.out.print(time[m]);
                break;
            case 2:
                System.out.print(time[20] + " " + time[m % 20]);
                break;
            case 3:
                System.out.print(time[21] + " " + time[m % 30]);
                break;
            case 4:
                System.out.print(time[22] + " " + time[m % 40]);
                break;
            case 5:
                System.out.print(time[23] + " " + time[m % 50]);
                break;
            default:
                if (m == 0) {
                    System.out.print("o'clock");
                }
        }

    }

}

❤ 点击这里 -> 订阅《PAT | 蓝桥 | LeetCode学习路径 & 刷题经验》by 柳婼

❤ 点击这里 -> 订阅《从放弃C语言到使用C++刷算法的简明教程》by 柳婼

❤ 点击这里 -> 订阅PAT甲级乙级、蓝桥杯、GPLT天梯赛、LeetCode题解离线版